Question

8. If alpha ,ß are the roots of the equation x^2-p(x + 1) -c =0 then find the value
of (alpha + 1 ) (ß + 1).​

Answer 1

$x^2-px-(c+p)=0$ which roots are $x=\alpha$, $x=\beta$

Know that :

$\alpha +\beta =p$

$\alpha \beta =-(c+p)$

Find the value.

$(\alpha +1)(\beta +1)$

$=\alpha \beta +(\alpha +\beta )+1$

$=-c-p+p+1$

$=-c+1$

The value is $-c+1$.