Question

8. If cos (90° -A)=0, then Sin (A+B) =

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Answer 1

Answer: sin B

Step-by-step explanation:

cos (90° -A)=0

or, sin A = 0

Then,

cos A = $\sqrt{1-sin^2 A}$ = $\sqrt{1-0}$  = 1

Now,

sin (A+B) = sin A *cos B +cos A *sin B

            = 0 * cos B  + 1* sin B

           = sin B