8. If cos (90°-A)=0, then Sin (A+B)=
A) O
B) 2
C) 3
D) None of the above
Answers
Given : Cos (90° - A) = 0
To Find : Sin (A + B)
Solution:
Method 1 :
Cos (90° - A) = 0
=> Sin A = 0
=> A = nπ
Sin (A + B) = Sin ( nπ + B) = ± SinB
Method 2 :
Cos (90° - A) = 0
=> Sin A = 0
Sin²A + Cos²A = 1
=> Cos²A = 1
=> Cos A = ±1
Sin (A + B) = SinACosB + CosASinB
=> Sin (A + B) = 0 *CosB + ( ±1)SinB
=> Sin (A + B) = 0 ± SinB
=> Sin (A + B) = ± SinB
Sin (A + B) = ± SinB
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Answer:
The answer is "0"
because (SinA+B) = 0
as per the formula.