Physics, asked by banajini1, 2 months ago

8. If g denoted the acceleration due to gravity at a point distant r from the centre of earth

of radius R then if r<R, then:

a. g ∝ 1/r^2

b. g ∝ 1/r

c. g ∝ r

d. g ∝ r^2​

Answers

Answered by Anonymous
38

Question:

If g denoted the acceleration due to gravity at a point distant r from the centre of earth of radius R then if r<R, then:

  • g ∝ 1/r^2
  • g ∝ 1/r
  • g ∝ r ✔︎
  • g ∝ r^2

Explanation:

According to the question,

  • Acceleration due to gravity is denoted by ‘g’.
  • Acceleration due to gravity at a point distance r fr the centre of the earth of radius R then if r<R then : ?

We know that,

Inside the earth \sf g' = \bigg( \dfrac{4}{3} \bigg) \pi Gr

\qquad \quad \longrightarrow g' \propto r

\qquad \quad \longrightarrow g \propto r

Answered by Anonymous
0

Question:

If g denoted the acceleration due to gravity at a point distant r from the centre of earth of radius R then if r<R, then:

g ∝ 1/r^2

g ∝ 1/r

g ∝ r ✔︎

g ∝ r^2

Explanation:

According to the question,

Acceleration due to gravity is denoted by ‘g’.

Acceleration due to gravity at a point distance r fr the centre of the earth of radius R then if r<R then : ?

We know that,

Inside the earth \sf g' = \bigg( \dfrac{4}{3} \bigg) \pi Gr

\qquad \quad \longrightarrow g' \propto r

\qquad \quad \longrightarrow g \propto r

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