Math, asked by aruniraj2007, 1 month ago

8. If one factor of x² - 4x-12 is (x-6), then the other factor is?​

Answers

Answered by bharathivenkatg6
0

Answer:

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Step-by-step explanation:

Determine what two numbers when added together make the coefficient of

x

, in this case

4

, and when multiplied together make the constant, in this case

12

. For this problem, the two numbers are

6

and

2

.

6

+

(

2

)

=

4

, and

6

×

(

2

)

=

12

.

The factorization of

x

2

+

4

x

12

=

(

x

2

)

(

x

+

6

)

.

Answered by tamannamanuja9
0

Answer:

Question :-

\begin{gathered} {x}^{2} - 4x - 12 = 0 \\ \end{gathered}

x

2

−4x−12=0

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

\begin{gathered} {x}^{2} - 4x - 12 = 0 \\ \\ {x}^{2} - 6x + 2x - 12 = 0 \\ \\ x(x - 6) + 2(x - 6) = 0 \\ \\ (x - 6)(x + 2) = 0\end{gathered}

x

2

−4x−12=0

x

2

−6x+2x−12=0

x(x−6)+2(x−6)=0

(x−6)(x+2)=0

Now split it into possible cases

\begin{gathered}(x - 6) = 0 \\ \\ (x + 2) = 0\end{gathered}

(x−6)=0

(x+2)=0

Hence,

\begin{gathered}x_1 = (6) \\ \\ x_2 = ( - 2)\end{gathered}

x

1

=(6)

x

2

=(−2)

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