Question

8. If Sin A=3/4 calculate Cos A and tan A

Answer 1

Answer:

$\frac{3}{2.64}$

Step-by-step explanation:

Given: sin A = 3/4

Using square trignometric indentity cos²a + sin²a = 1

Solution:

cos A = $\sqrt{1-sin^2A}$

         = $\sqrt{1-(\frac{3}{4}) ^2}$

         = $\sqrt{1-\frac{9}{16}}$

         =$\sqrt{\frac{7}{16}}$

         = $\frac{2.64}{4}$

tan A = $\frac{sin A}{cos A}$

         = $\frac{\frac{3}{4} }{\frac{2.64}{4} }$

         = $\frac{3}{2.64}$

Answer 2

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To Solve:

• CosA and TanA

Given:

• SinA = 3/4

Solⁿ:

SinA = P/H = 3/4

Perpendicular = 3

Hypotenuse = 4

Pythagoras Theorem:

H² = B² + P²

(4)² = B² + (3)²

16 = B² + 9

16 - 9 = B²

7 = B²

√7 = B

So,

CosA = B/H

CosA = B/H= √7 / 4

TanA = P/B

= 3/√7

HOPE IT HELPS

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