Question

8. If sin A/
sinB
=m and cosA/cosB
=nthen find the value of tan B
cos B
n² <1 ‹ m²​

Answer 1

Answer:

Solution:

Given, sinAsinB=m

⇒sinA=msinB…(i)

and cosAcosB=n

⇒cosA=ncosB…(ii)

Squaring (i) and (ii) and then adding, we get

1=m2sin2B+n2cos2B

⇒1cos2B=m2sin2Bcos2B+n2 (Dividing by cos2B)

⇒sec2B=m2tan2B+n2

⇒1+tan2B=m2tan2B+n2

⇒tan2B=1−n2m2−1

⇒tanB=±1−n2m2−1−−−−√

Step-by-step explanation:

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