Question

8. If tan A = 5/12, find the value of (sin A +cos A). sec A.​

Answer 1

Answer:

$\sf \: tanA = \frac{5}{12} = \frac{p}{b}$

$\sf \: h = \sqrt{12²+ 5² }$

$\sf \: h = \sqrt{144+ 25 }$

$\sf \: h = \sqrt{169}$

$\sf \: h = 13$

$\boxed{ \sf \: now , sinA = \frac{p}{h} = \frac{5}{13} }$

$\boxed{ \sf \: cosA = \frac{b}{h} = \frac{12}{13} }$

$\boxed{ \sf \: secA = \frac{h}{b} = \frac{13}{12} }$

$\sf \: now, \: putting \: these \: value \: on$

$\sf \: (sinA + cosA )secA$

$\sf \: \implies( \frac{5}{13} + \frac{12}{13} ) \frac{13}{12}$

$\sf \: \implies \:12+ \frac{5}{13} × \frac{13}{12}$

$\sf \: \implies \: \frac{17}{13} × \frac{13}{12}$

$\sf \: \implies \frac{17}{12} \: Answer$

Step-by-step explanation:

Hope it helps you