Question

8. If the base of a right angled triangle is 8 cm and the hypotenuse is 17 cm. Find its
area.
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Answer 1

Answer:

60

Step-by-step explanation:

Answer 2

$\huge\bold\green{H}\orange{E}\red{L}\purple{L}\pink{O}$

according to Pythagoras theorem

the square of the two sides of a triangle in a right angle is equal to the square of hypotenuse.

let the height be x

${x}^{2} + {8}^{2} = {17}^{2}$

${x}^{2} + 64 = 289$

${x}^{2} = 289 - 64$

${x}^{2} = 225$

$x = 15 \:(as \: {15}^{2} = 225)$

base =8

height=15

$area \: of \: triangle = \frac{1}{2} \times base \times height$

$\frac{1}{2} \times 8 \times 15 \\ \\ \frac{1}{2} \times 120$

$\frac{120}{2} = 60$

hope this helps you