Question

8. If the first term of an AP is 2 and common difference is 4, then find the sum of
its first 40 terms
​

Answer 1

Answer:

3200

Step-by-step explanation:

a = 2

d = 4

Sn = n/2 {2a+(n-1)d}

S40 = 40/2 [2(2) + (40-1)4]

S40 = 20[4+156]

S40 = 20(160)

S40 = 3200

Answer 2

Answer:

S40=3200

Step-by-step explanation:

hope it helps you