Question

8.
If the length of a chord of a circle at a distance of 24 cm from the centre of the circle is 36 cm,
find the length of the greatest chord of the circle.
(a) 80 cm (b) 70 cm (c) 60 cm (d) 50 cm
​

Answer 1

Answer:

b......

Step-by-step explanation:

follow me......I hope this helps you

Answer 2

Answer:

c. 60cm

Step-by-step explanation:

Let AB be a chord having length 36cm

Let O be the center

Make a perpendicular line from OM to AB

OM = 24cm

A perpendicular drawn from the center to a chord, bisects the chord

∴ AM =BM

BM= $\frac{1}{2}$×AB = $\frac{1}{2}$× 36 = 18cm

Join OB

In ΔOMB, $OB^{2}$ = $OM^2+MB^2$

$OB^{2}$ = $24^{2} +18^{2}$

$OB^{2}$ = 576 + 324

$OB^{2}$ = 900

OB = $\sqrt{900}$

∴ OB = 30 cm

As B is on circumference of the circle, OB is the radius.

We know that Longest chord is the Diameter

And Diameter = radius × 2

∴ Diameter = 30 × 2 = 60cm

I hope it helps.

Plz mark me the brainliest