Question

8. If the sum of the zeroes of the
polynomial 2 x^3 - 3k x^2 + 4x - 5 is 6, then
the value of k is
(2 Points)
O 2
4
0-2
-4​

Answer 1

Comparing the given polynomial with ax^3+bx^2+cx+d=0, we get

a=2, b=-3k, c=4 and d =-5

Sum of zeroes(α+β+γ)=-b/a=3k/2

Sum of zeroes(α+β+γ)= 6 ....(given)

3k/2=6

3k=12

k=12/3

k=4

Answer 2

Answer:

Step-by-step explanation:

Comparing the given polynomial with ax^3+bx^2+cx+d=0, we get

a=2, b=-3k, c=4 and d =-5

Sum of zeroes(α+β+γ)=-b/a=3k/2

Sum of zeroes(α+β+γ)= 6 ....(given)

3k/2=6

3k=12

k=12/3

k=4