Question

8) If the volume of the cylinder is 100 cm³, then the volume of another cylinder whose
height is same but radius of the base is doubled Is​

Answer 1

Answer:

Given, h2=9cm,d2=40cm

r2=240=20cm,h1=108cm.

Volume of the cone = Volume of the cylinder.

31πr12h1=πr22h2

31πr12(108)=π(20)2(9)

r12(108)=3×9×(20)2

r12=1083×9×400

r12=100cm.

r1=10cm

Thus, the radius of the base of the cone is 10 cm.

Step-by-step explanation:

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Answer 2

Answer :-

Let us assume that, height of first cylinder is h cm and radius is r cm.

so,

→ Volume of first cylinder = πr²h = 100 cm³ ---------- Eqn.(1)

now, radius of another cylinder will be 2r cm and height is same h cm.

then,

→ Volume of another cylinder = π(2r)²h = π * 4r² * h = 4πr²h .

putting value of Eqn.(1) , we get,

→ Volume of another cylinder = 4 * πr²h = 4 * 100 = 400 cm³ (Ans.)

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