Question

8.
If two slits in YDSE experiment have their width
ratio 1:9, then ratio of minimum to maximum
intensity in the interference pattern would be
[NCERT Pg. 366]
(1) 1:4
(2) 1:8
(3) 1:12
(4) 1:2
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Answer 1

Answer:

1:4

Explanation:

Intensity ratio = 1:9(given)

Amplitude ratio = 1:3 (take square root of intensity)

Maximum amplitude = 1+3 =4

Minimum amplitude = 3-1 = 2

Minimum to maximum amplitude = 2:4= 1:2

Intensity minimum to maximum = 1:4(square of amplitude)

Hope it helps!