Question

8. If two zeroes of a Polynomial x³ - 3x² + 2 are 1 + √3 and 1 - √3 , then find the third zero.​

Answer 1

$\Huge{\textbf{\textsf{{\purple{Ans}}{\pink{wer}}{\color{pink}{:}}}}}$

$Syppose\:, third\:\:root \:is \:\:\alpha$

$so \: \: from \: the \: poliomial \\ (1 + \sqrt{3} )(1 - \sqrt{3} ) \times \alpha = - 2 \\ \implies \: \alpha = \frac{ - 2}{(1 + \sqrt{3}(1 - \sqrt{3} ) } = \frac{ - 2}{ {1}^{2} - {( \sqrt{3} ) }^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: = \frac{ - 2}{1 - 3} = \frac{ - 2}{ - 2} = 1$

so third root is = - 1

why did you report my previous answer?

My answer was correct