Question

8. If x = 1 find the value of x³– 2x² – 7x +5 answer​

Answer 1

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Here,

x=1

we have to find the value of x³– 2x² – 7x +5

According to the question,

• x³– 2x² – 7x +5
• (1)³– 2(1)² – 7(1) +5
• 1-(2)-(7)+5
• 6-9
• -3

Answer 2

Answer:

\frac{1}{2- \sqrt{3} } = \frac{1}{2- \sqrt{3} } * \frac{2+ \sqrt{3}}{2+ \sqrt{3} } = \frac{ 2+ \sqrt{3}}{2^2-3}=\frac{ 2+ \sqrt{3}}{1} = 2+ \sqrt{3}

x³ - 2x² - 7x + 5

(2+ \sqrt{3})^3 - 2(2+ \sqrt{3})^2 - 7(2+ \sqrt{3}) + 5

8 + 3 \sqrt{3} + 6 \sqrt{3} (2+ \sqrt{3}) - 2(4+3+4 \sqrt{3}) - 7(2+ \sqrt{3}) + 5

8 + 3 \sqrt{3} + 12 \sqrt{3} + 18 - 14-8 \sqrt{3} - 14-7 \sqrt{3} + 5

31 + 15 \sqrt{3} - 28-15 \sqrt{3}

3

Step-by-step explanation:

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