Question

8. If |x-1| + |y-2|+ (z-3) ²< 0 then find the value of x + y + z (where x, y, z € R)​

Answer 1

Step-by-step explanation:

Apr-2018 — quotient and r is remainder (0 ≤ r ≤ 4) ... (b) If z = a + ib is the complex number, then a and b are called ... For any complex number z = x + i y, there exist 0, i.e., (0 + 0i)

Answer 2

Squaring both sides

$(x + y +z) {}^{2} = x {}^{2} + y {}^{2} + z {}^{2}$

$+ 2(xy + yz + zx)$

we can substitute given values

$(x + y + z) {}^{2} = 18 +2 \times 9$

$(x + y + z) {}^{2} = 36$

$(x + y + z) = 6$