8. If x = 3 + 2
![\sqrt{2} \sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7D+)
, find :
(i)1/x
(ii)x-1/x
(iii)(x-1/x)^3
(iv)x^3-1/x^3
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Answered by
0
Answer:
Answer is in the above picture
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![](https://hi-static.z-dn.net/files/df3/617f063e3b71937e0fe09b09c593ba7f.jpg)
Answered by
1
Answer:
i) 1/3+2=1/5
ii)3+2-1/3+2=4/5
iii)64/125
iv)125-1/125=124/125
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