Question

8. If x3-3x2+4x-4 is a polynomial, then one of its factors is
a)x-1
b),x+1
c) x-2
d) x+4
​

Answer 1

Answer:

By using factor theorem

x-1 is a factor of given p(x)

Answer 2

Answer:

Option c is the answer

Step-by-step explanation:

Given polynomial is p(x)=x³-3x²+4x-4

we know that by factor Theorem

If (x-a) is a factor of p(x) then p(a)=0

now

1)consider x-1

if x-1 is a factor then p(1)=0

p(1)=(1)³-3(1)²+4(1)-4

=>p(1)=1-3+4-4=-2

so it is not a factor

2) Consider x+1

=>p(-1)=(-1)³-3(-1)²+4(-1)-4

=>p(-1)=-1-3-4-4=1-11=-10

x+1 is not a factor

3)consider x-2

=>p(2)=2³-3(2)²+4(2)-4

=>p(2)=8-12+8-4=16-16=0

x-2 is a factor

4)Consider x+4

=>p(-4)=(-4)³-3(-4)²+4(-4)-4

=>p(-4)=-64-48-16-4=-132

x+4 is not a factor