Question

8. If y = -3, then find the value of y^3 + 2y^2 – 3y


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Answer 1

Answer:

y=-3

=y^3+2y^2-3y

=(- 3)^3 + 2(- 3)^2 - 3(-3)

=-27+ 18 +9

=- 27+27

=0

Answer 2

The correct answer to the following question will be "0"

Step-by-step explanation:

According to the question, the given value of y is:

y= -3

Now, by putting the value of y in the given equation, we get

= y³+2y²-3y

= (-3)³+2(-3)²-3(-3)

After solving the powers, we get

= (-3)×(-3)×(-3)+2(-3)×(-3)-3(-3)

Now, solving the brackets, we get

= -27+18+9

= 0

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