8. If y = -3, then find the value of y^3 + 2y^2 – 3y
Answers
Answered by
2
Answer:
y=-3
=y^3+2y^2-3y
=(- 3)^3 + 2(- 3)^2 - 3(-3)
=-27+ 18 +9
=- 27+27
=0
Answered by
3
The correct answer to the following question will be "0"
Step-by-step explanation:
According to the question, the given value of y is:
y= -3
Now, by putting the value of y in the given equation, we get
= y³+2y²-3y
= (-3)³+2(-3)²-3(-3)
After solving the powers, we get
= (-3)×(-3)×(-3)+2(-3)×(-3)-3(-3)
Now, solving the brackets, we get
= -27+18+9
= 0
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