Question

8. In a AABC, ZA=xº, ZB=(3x – 2)°, 2C=yº. Also, ZC - ZB=9º. Find the three angles.
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Answer 1

Answer:

I am not sure but this your answer

Step-by-step explanation:

It’s given that,  ∠A = x°,  ∠B = (3x – 2)°,  ∠C = y°  Also given that,  ∠C – ∠B = 9°  ⇒ ∠C = 9° + ∠B  ⇒ ∠C = 9° + 3x° − 2°  ⇒ ∠C = 7° + 3x°  Substituting the value for  ∠C = y° in above equation we get,  yo = 7° + 3x°  We know that, ∠A + ∠B + ∠C = 180° (Angle sum property of a triangle)  ⇒ x° + (3x° − 2°) + (7° + 3x°) = 180°  ⇒ 7x° + 5° = 180°  ⇒ 7x° = 175°  ⇒ x° = 25°  Hence, calculating for the individual angles we get,  ∠A = x° = 25° ∠B = (3x – 2)° = 73°  ∠C = (7 + 3x)° = 82°  Therefore, ∠A = 25°, ∠B = 73° and ∠C = 82°.Read more on Sarthaks.com - https://www.sarthaks.com/633600/in-a-abc-a-x-b-3x-2-c-y-also-c-b-9-find-the-three-angles