Question

(8) In A ABC, AB = 6 √3 cm, AC = 12 cm, BC = 6 cm. Find measure of angle A (A) 30°(B) 60° (C)45°(D) 90°​

Answer 1

Answer:

The correct answer is : (A) 30°

Hope it helps

Answer 2

Answer:

Given,

In triangle ABC

AB\ =\ 6\sqrt{3}AB = 6

3

AC = 12 cm

and BC = 6 cm

From the given data we have,

AC^2\ =\ 12^2\ =\ 144AC

2

= 12

2

= 144

BC^2\ +\ AB^2\ =\ 6^2\ +\ (6\sqrt{3})^2\ =\ 144BC

2

+ AB

2

= 6

2

+ (6

3

)

2

= 144

Hence, we can see that

AC^2\ =\ AB^2\ +\ BC^2AC

2

= AB

2

+ BC

2

So, the given triangle ABC is a right angle triangle. So, we cam write that

tanA\ =\ \dfrac{perpendicular}{base}tanA =

base

perpendicular

=\ \dfrac{6}{6\sqrt{3}}=

6

3

6

=\ \dfrac{1}{\sqrt{3}}=

3

1

So, we can write

∠A = 30°

So, the measurement of angle A of triangle ABC is 30°.

Step-by-step explanation:

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