Question

8. In a bag containing 9 new coins and 3 old coins. Two coins are drawn one by one without
replacement, what is the probability that

(a) both of them are new coins?
(b) at least one old coin is selected?

Answer 1

Answer:

i hope you will understand....

Answer 2

(a) $\frac{6}{11}$ or 0.5454

(b) $\frac{5}{11}$ or 0.4545

Step-by-step explanation:

The number of new coins in a bag = 9

The number of old coins in a bag = 3

total number of coins = 9 + 3 = 12

(a) two coins are drawn one by one without replacement.

probability that first drawn is new coin  p₁ = $\frac{9}{12}=\frac{3}{4}$

probability that second drawn is new coin  p₂ = $\frac{8}{11}$

Probability that both of them are new coins

P = p₁ × p₂

$P=\frac{3}{4}\times \frac{8}{11}=\frac{6}{11}$  or  0.5454

(b) p (at least 1 old) = 1 - P

                               = $1-\frac{9}{12}\times \frac{8}{11}$

                              = $1-\frac{6}{11}$

                              =  $\frac{5}{11}$   or  0.4545

(a) $\frac{6}{11}$ or 0.5454

(b)  $\frac{5}{11}$ or 0.4545

Learn more about probability : https://brainly.in/question/8795851