Question

8. In a certain triangle, one angle is twice as
large as another and six times as large as the
third. Find the measure of each angle?

Answer 1

Step-by-step explanation:

Let the 3 angle be A, B, C.

Let the larger angle be A.

A=2B A=6C

B=A/2. C=A/6

In a triangle the sum of all angles is 180°

=>A+B+C=180°

=>A+A/2+A/6=180°

=>10A/6=180

A=(180×6)/10

A=108°

B=A/2=108°/2. C=A/6=108°/6

B=54°. C=18°

The measure of angles are 108°,54°,18°.