Question

8. In a class six students got 30, 50 80, 70, 20, 5c marks. What is the median score of the class
​

Answer 1

Step-by-step explanation:

umber of students=n=50

2

n

=

2

50

=25,

As 25<31,

So 30−40 is the median class.

l is the lower limit of median class, so l=30

h is the size of class interval, so h=40−30=10

f is the frequency of median class, so f=16

F is the cumulative frequency of class preceding the median class, so F=15

Median=l+(

f

2

n

−F

)×h

Median=30+(

16

2

50

−15

)×10

Median=30+(

16

10

)×10

Median=30+(

16

100

)

median 36.5

an is=36.25

Answer 2

The Median Score Of The Class Is 52.5

Given

Total number of students = 6

Marks obtained = 30, 50, 80, 70, 20, 55

TO FIND

Median score of the class.

SOLUTION

We can simply solve the above problem as follows -

Total number of data, n = 6

Marks = 30, 50, 80, 70, 20, 5c

Since the given observation of marks is on even.

Median will be equal to the mean of the two middle values.

$median \: = \frac{1}{2} [( \frac{n}{2})th \: observation + ( \frac{n}{2} + 1)th \: observation$

Where, n = total number of observation

First, we need to arrange the data into ascending or descending order ;

Ascending order :

20, 30, 50, 55, 70, 80

median = 50+55/2 = 52.5

Hence, the median score of the class is 52.5

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