Math, asked by anantrajusharma, 7 months ago

8
In a committee, 50 people speak French, 20 speak Spanish, and 10 speak both Spanish and French. How many speak at least one of these two languages?

Answers

Answered by AnantSharmaGUNA
4

Let F be the set of people who speak French,

and S be the set of people who speak Spanish.

Number of people who speak French = n(F) = 50

Number of people who speak Spanish = n(S) = 20

Number of people who can both speak French and Spanish

= n(F ∩ S)

= 10

Number of people who speak at least one of these two languages = n(F ∪ S)

We know that-

n(F ∪ S) = n(F) + n(S) - n(F ∩ S)

= 50+20 - 10

= 60

∴ n(H ∩ E) = 60

Thus, 60 people can speak at least one of French or Spanish.

JAI SHREE KRISHNA

Answered by Bharatbishnoi229
3

Let F be the set of people in the committee who speak French

,and S be the set of people in the committee who speak Spanish

Number of people who speak French = n(F) = 50,

Number of people who speak Spanish = n(S) = 20, %3D Number of people who speak French & Spanish

=n(S n F) = 10

People who speak atleast on of the language n(S U F)

wkt

n(S U F) = n(S) + n(F) – n(S n F) =

20 + 50 –10 = 70 - 10 = 60

Thus, 60 people in the committee speak at least one of the two languages.

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