Question

8. In a continuous frequency distribution class mark of a class is 55 and upper limit is 57, then its lower limit is ————– 53

Answer 1

SOLUTION

TO FILL IN THE BLANK

In a continuous frequency distribution class mark of a class is 55 and upper limit is 57, then its lower limit is ______

CONCEPT TO BE IMPLEMENTED

Class Mark :

For any grouped frequency table with class intervals, the middle value of the class limits or the class boundaries of any class is called class mark of the class

EVALUATION

Let lower limit = x

Thus we get

Upper limit = 57

Lower limit = x

Class mark of a class = 55

So by the given condition

$\displaystyle \sf \: \frac{57 + x}{2} = 55$

$\displaystyle \sf \implies 57 + x= 110$

$\displaystyle \sf \implies x= 110 - 57$

$\displaystyle \sf \implies x = 53$

FINAL ANSWER

In a continuous frequency distribution class mark of a class is 55 and upper limit is 57, then its lower limit is 53

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Answer 2

Answer:

The lower limit is $53$.

Step-by-step explanation:

The middle value of the class limits or the class boundaries of any class for grouped frequency table with class intervals is called class mark of the class.

Assuming lower limit be $x$

Upper limit = $57$

Class mark of a class = $55$

Using the given conditions

$(57+x)/2=55$

$57+x=110$

$x=110-57$

$x=53$

Hence, In a continuous frequency distribution class mark of a class is $55$and upper limit is $57$, then its lower limit is $53$.

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