Question

8. In a double slit interference experiment, the distance between the slits is 0.05 cm and screen is
2 m away from the slits. The wavelength of light
is 8.0 x 105 cm. The distance between successive fringes is
(C.PM.T. 1990)
(1) 0.24 cm
(2) 3.0 cm
(3) 1.28 cm
(4) 0.32 cm
​

Answer 1

Answer:

$y \: = \frac{wave \: length \: \times distance \: of \: screen}{distance \: of \: screen} \\ y \: = \frac{8 \times {10}^{ - 7} \times 2 }{5 \times {10}^{ - 4} } \\ y \: = 0.32 \: cm$

hope the answer will help you

Explanation:

4.is the correct answer

Answer 2

Answer:

.32 Cm

Explanation:

Given

distance between the slits=.05 cm

Screen=2m away

Wavelength of light=8.0×105 cm

Find

Distance between successive fridges

Solution

β=λD/d

=16/5×$10^{-3}$

=$3.2*10^{-3}$

=.32 Cm

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