Question

8.In a village, there are cows and peacocks. If there are total 150 heads and 380 legs. How many peacocks are there?
A) 115
B) 110
C) 90
D) 105​

Answer 1

Answer:

110 peacocks

Step-by-step explanation:

Let the number of peacocks be x and number of cows be y.

We know that, peacock has 2 legs and cow has 4 legs.

Given,

x + y = 150 ---(1)

2x + 4y = 380 ---(2)

Multiplying eq 1 by 2

2x + 2y = 300 ---(3)

Subtracting eq 3 from eq 2

2x + 4y = 380

2x + 2y = 300

2y = 80

y = 40

Putting y = 40 in eq 1

x + 40 = 150

x = 110

Answer 2

Let the number of cows be $x$

Let the number of peacocks be $y$

We know that a cow have 1 head and 4 legs, and a peacock have 1 head, and 2 legs.

Hence, A.T.Q.

$x \times 1 + y \times 1 = 150 \\ x + y = 150 \: \: \: \: ...(i)$

$x \times 4 + y \times 2 = 380 \\ 4x + 2y = 380 \\ 2x + y = 190 \: \: \: \: ...(ii)$

Subtracting (i) from (ii)

$x = 40$

And $y=110$

Therefore, the number of peacocks is B) 110