Question

8. In Fig. C and D are points on the semi-circle
described on BA as diameter. Given ZBAD = 70°
and m ZDBC = 30°. Calculate ZABD and ZBDC.
1/30°
300
70°​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

<DBA=20

BECAUSE <BDA=90[angle at the circumference of a semi circle]

then

70+<BCD=180

or, <BCD=110

again,

70+30+20+110+90+<BDC=360

or <BDC=40