Question

8. In figure, AD = DB and ZB is a right angle. Determine
sin? 0 + cos2 0.
AN
64
Da
Ꮎ
C
B​

Answer 1

Answer:

AB= a

⇒ AD + DB = a

⇒ AD + AD = a

⇒ 2 AD = a

⇒ AD = 2a

Thus, AD = DB = 2a

By Pythagoras theorem, we have 

AC2=AB2+BC2

⇒b2=a2+BC2

⇒BC2=b2−a2

⇒BC=b2−a2

Thus, in ΔBCD, we have

Base = BC = b2−a2 and Perpendicular = BD = 2a

Applying Pythagoras theorem in Δ BCD, we have

⇒BC2+BD2=CD2

⇒(b2−a2)+(2a)2=CD2

⇒CD2=b<

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