Question

8. In how many years will 1000 amount to
1400 at the rate of 4% per annum simple interest?​

Answer 1

QUESTION:–

In how many years will 1000 amount to

1400 at the rate of 4% per annum simple interest?

GIVEN:–

PRINCIPLE=1000

AMOUNT=1400

RATE=4%

FIND:–

TIME

FORMULA:–

SIMPLE INTEREST=(PRINCIPLE×TIME×RATE)/100

AMOUNT=PRINCIPLE+SIMPLE INTEREST

SOLUTION:–

AMOUNT=RS 1400

PRINCIPLE=RS 1000

therefore , SIMPLE INTEREST=RS (1400‐1000)=RS 400

SI=(P×R×T)/100

400=1000×4×T/100

=>400×100/1000×4=T

=>10=T

ANSWER:–

TIME=10 YEARS

Answer 2

$\huge \fbox{Answer}$

$\large \underline {\underline{ \frak{ \color{red} Given: - }}}$

$\mapsto{ \sf{Amount(A)=₹1,400}}$

$\mapsto \sf{Principal (P)=₹1,000}$

$\mapsto \sf{Rate(r)=4\%}$

$\large \underline {\underline{ \frak{ \color{blue}To \: find: - }}}$

${ \leadsto{ \sf{In \: how \: many \: years \: the \: value \: of}}} \\ \sf{ \: \: \: \: principal \: change \: into \: amount. }$

$\large \underline {\underline{ \frak{ \pink{Formula \: required: - }}}}$

$\star{ \boxed{ \rm{Time(t)= \frac{Simple \: Interest(S.I.) \times 100}{Principal( P) \times Rate(r)} }}} \star$

$\star{ \fbox{S. I.=Amount(A)-Principal(P)}} \star$

$\large \underline {\underline{ \frak{ \color{indigo}According \: to \: Question: - }}}$

$\sf{:: \implies{Simple \: Interest(S. I.)=Amount(A)-Principal(P)}}$

$\sf{:: \implies{ Simple \: Interest(S.I.)= ₹1,400-₹1,000}}$

$\sf{:: \implies{ Simple \: Interest(S.I.)= ₹400}}$

$\bf{Then,}$

${ \sf{ : : \implies{Time(t)= \frac{Simple \: Interest(S.I.) \times 100}{Principal( P) \times Rate(r)} }}}$

${ \sf{ : : \implies{Time(t)= \frac{400 \times 100}{1,000 \times 4} }}}$

${ \sf{ : : \implies{Time(t)= \frac{ \cancel{400} \times 100}{1,000 \times \cancel4} }}}$

${ \sf{ : : \implies{Time(t)= \frac{ 100 \times 100}{1,000}}}}$

${ \sf{ : : \implies{Time(t)= \frac{ 10,000}{1,000}}}}$

${ \sf{ : : \implies{Time(t)= 10years}}}$

$\bf{Hence,}$

$\fbox{Time \: taken \: to \: change \: the \: value \: is \: 10years.}$