Question

8.
In the arrangement shown in figure if a force of 2mg
applied at the free end of the
rope,ascend with an acceleration of
(A)g/2
(B)g
c)g/3
(D) 2g​

Answer 1

Answer:

b

Explanation:

force due to m = mg so net force 2mg - mg = mg so g

Answer 2

Answer:

b

Explanation:

here

as tension in rope is 2mg and the force due to gravity on block is mg in opposite direction ..

so net force=2mg-mg=mg

so acceleration=mg/m=g