Question

8. In the given figure,AB, AC and PQ are tangents. If AB = 5 cm, then find the perimeter of
ΔΑΡQ.
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Answer 1

Answer:

Since AB and AC are the tangents from the same point A

∴AB=AC=5cm

Similarly, BP=PX and XQ=QC

Perimeter of ΔAPQ=AP+AQ+PQ

=AP+AQ+(PX+XQ)

=(AP+PX)+(AQ+XQ)

=(AP+BP)+(AQ+QC)

=AB+AC=5+5=10cm.

Answer 2

Answer:

AB = 5 cm also AC = 5 cm

PB = PX , OX = OC

perimeter ∆ ABC = AP+ PO+ AO

= AP+ PB + OC + AO

= AB+ AC

= 5+5= 10