8. In the given figure, ABCD is a rectangle in which AB = 60 cm and BC = 40 cm. If P, Q, R and S be thé mid-points of AD, DC, CB and BA, find the area of the shaded region. Ans 1200 cm sq
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3
Answer:
given
ab=60cm
bc=40cm
p,q,r,s are the midpoints
to find
area of shaded region
solution:
AS=SB= 30cm
BR=CR= 20cm
join p and r, q and s
in triangle QOR
base=OR=30cm
height= OQ= 20cm
area of triangle QOR=
1/2 ×B×H
1/2×30×20
= 300cm^2
area of the shaded region = 300×4
=1200cm^2
Answered by
0
Answer:
area of the rectangle ABCD is 60cm×40cm
=2400 sq cm
In the figure,
P is the midpoint of AD
so,AP=40/2 cm=20cm=PD
similarly, BR=RC=20cm
again Q is the midpoint of DC
so,DQ=QC=60/2 cm=30 cm
area of the triangle PDQ,
1/2.DQ.PD sq cm
=30×20/2 sq cm=300 sq cm
similarly,triangle RCQ=300sq cm
triangle SBR=300sq cm
triangle APS÷300sq cm
area of the shaded region is
(2400-4.300)sq cm
=(2400-1200) sq cm
=1200sq cm
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