8.In the given figure, find the value of 10n.
(a) 200°
(c) 202°
(b) 100°
(d) 20°
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Answer:
theforcewhichisopposingfrictionwillbe
totalforce−forceneededtomovetheblocks
f=ma
f=(5+5)(1)
=10newton
sothenetfrictionalforcewillbe
=30−10
=20newton
sothevalueofkwillbe
10k=20newton
k=
10
20
k=2
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