Question

8.
In the given figure, O is the centre of the circle and PT is the tangent to the circle. If PQ

is a chord such that ZQPT = 50°, then find ZPOQ.
​

Answer 1

Step-by-step explanation:

Given, PQ is a chord of a circle with center O. 

Also, ∠QPT=60°.

Let x be the point on the tangent PT.

∠QPT+∠OPT=90

⇒∠OPT=300−∠QPT=900−600=300

In ΔPOQ 

∠POQ=180−(∠OPQ+∠PQO)=180−30−30=1200

Minor arc ∠POQ=1200

Therefore Major arc ∠POQ=3600−1200=2400

Angle subtended by  an arc at centre is double the angle subtended by it on remaining part of circle

∴∠QRP=21∠POQ=1200

Answer 2

Step-by-step explanation:

hiiii don't know pata nahi