Question

8. In the given figure. PQRS is a cyclic quadrilateral. If
ZPSR = 110° and ZPRQ = 65°, then ZRPQ is :
(b) 55
(c) 45°
(c) 35°​

Answer 1

Answer:

anglePRQ=45°

Step-by-step explanation:

SINCE ANGLES IN THE SAME SEGMENT ARE EQUAL therefore 65+x=110°

x=45°

Answer 2

Answer:

(c) 45°

Step-by-step explanation:

The sum of opposite sides of a cyclic quad. is 180°.

ZPSR+ZRQP=180°

110°+ZRQP=180°

ZRQP=70°

NOW

In triangle RPQ-

ZRQP+ZPRQ+ZRPQ=180°( Angle Sum Property of a Triangle)

70°+65°+ZRPQ=180°

ZRPQ=180-135°=45°

ZRPQ=45°