8. In the right angle triangle ABC <B =90° Square BDLK, ABDE and ACGF are drawn on the sides BC.
AB and AC as shown in the figure then the area of the square on the side AC is
A) 25 sq cm B) 50 sq cm
c) 25 sq cm D)100 sq cm
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I don't know the answer sorry bro
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Ac=bc=ab
consider∆ABC
ac²=ab²+bc². ( Pythagoras theorem)
ac²=ab²+(2bd)²
ac²=ab²+4bd². ------(1)
consider∆ABC
ad²=ab²+bd².
(do your self). ------(2)
subtract equation (1) and (2)
ac²-ad²=3bd²
ac²-ad²=3cd². [bd=cd]
ac²=ad²+3cd²
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