Question

8. In triangle ABC, = 90°, AB = 8 cm = (i) Find length of Bc and AC (Find the values of sin A, CAS A
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Answer 1

Answer:

$\boxed{\tt \red{SinB = 15/17}}$

$\boxed{\tt \red{CosB = 8/17}}$

Step-by-step explanation:

Since Triangle is right angle triangle.

So, By using Pythagoras theorem we can find the length of remaining side (in this case base).

AB= 8cm, BC = 17 cm

AC = √{(BC)^2 - (AB)^2} = √{17^2 - 8^2} = 15

SinB = AC/BC = 15/17

CosB = AB/BC = 8/17

tanB = AC/AB = 15/8

Since Angle ( A+B+C) = 180

Angle (90+B+C) = 180

Angle (B+C) = 90

so, Angle (C) = 90- Angle (B)

Now, tan(90- B) = tanC = 8/15

tanB × tan (90-B) = 15/8 × 8/15 = 1

$\purple{\rule{45pt}{7pt}}\red{\rule{45pt}{7pt}}\pink{\rule{45pt}{7pt}}\blue{\rule{45pt}{7pt}}$