8. In triangle ABC, AB = AC then ————– A.
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Answer:
Given: △ABC, AB=AC=8, BC=4 and AP=6
In ΔABC,
BC
AB
=
4
8
=2,
In ΔBPC,
CP
BC
=
2
4
=2
Now, in △ABC and △BPC
BC
AB
=
CP
BC
∠ABC=∠C.
Therefore, by SAS, ΔABC∼ΔBPC
Thus,
BP
AB
=
BC
AC
BP
8
=
4
8
BP=4 cm
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