8 into a cube b square c square + a square b cube c square + a square b square c square divided by 2 a square b square c square
Answers
Answered by
0
Answer:
4*(a+b+1)
Step-by-step explanation:
8*[a^3b^2c^2+a^2b^3c^2+a^2b^2c^2]/2a^2b^2c^2
=[8*a^2b^2c^2(a+b+1)]/2a^2b^2c^2
=4(a+b+1)
Similar questions