Question

8-k(6)+k²=0 find value of k

Answer 1

8-6k+k^2=0
Now,
K^2-6k+8=0

Factorize,
(k-2) (k-4)
Therefore,
k=2 or 4

Answer 2

value of K is 3&1

B2-4Ac=0

4(2k-3)2-4(5k-6) jk-2)=0

4k2-12k+9-5k2-16k+12)=0

-k2+4k-3=0

or

k2-4k +3= 0

(k-3) (k-1) =0

K= 3 & K= 1