8 kg of potatoes and 5 kg of carrots cost $28 whereas 2 kg of potatoes and 3 kg of carrots cost $11.20 what is the cost of 1 kg of each item??
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Cost of 1 kg of Potatoes = $ 2
Cost of 1 kg of Carrots = $ 2.40
Explanation -
Let the cost of 1 kg of Potatoes = x
Let the cost of 1 kg of Carrots = y
ATQ , 8x + 5y = 28 - 1)
2x + 3y = 11.20 - 2)
Multiplying 2) by 4
8x + 12y = 44.80 - 3)
Applying Elimination method in 1) and 3)
8x + 5y = 28.00
8x + 12y = 44.80
- - -
---------------------------
0 + -7y = - 16.80
y = 16.8/7
y = 2.4
Putting the value of "y" in 1)
8x + 5(2.4) = 28
8x + 12 = 28
8x = 16
x = 16/8
x = 2
Cost of 1 kg of Carrots = $ 2.40
Explanation -
Let the cost of 1 kg of Potatoes = x
Let the cost of 1 kg of Carrots = y
ATQ , 8x + 5y = 28 - 1)
2x + 3y = 11.20 - 2)
Multiplying 2) by 4
8x + 12y = 44.80 - 3)
Applying Elimination method in 1) and 3)
8x + 5y = 28.00
8x + 12y = 44.80
- - -
---------------------------
0 + -7y = - 16.80
y = 16.8/7
y = 2.4
Putting the value of "y" in 1)
8x + 5(2.4) = 28
8x + 12 = 28
8x = 16
x = 16/8
x = 2
SHAHGUL:
can you show me your doing method.....?
Cost of 1 kg of Carrots = $ 2.40
Explanation -
Let the cost of 1 kg of Potatoes = x
Let the cost of 1 kg of Carrots = y
ATQ , 8x + 5y = 28 - 1)
2x + 3y = 11.20 - 2)
Multiplying 2) by 4
8x + 12y = 44.80 - 3)
Applying Elimination method in 1) and 3)
8x + 5y = 28.00
8x + 12y = 44.80
- - -
---------------------------
0 + -7y = - 16.80
y = 16.8/7
y = 2.4
Putting the value of "y" in 1)
8x + 5(2.4) = 28
8x + 12 = 28
8x = 16
x = 16/8
x = 2
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