Question

(8 m (a) The sum of squares of the first n natural numbers is given by n(n + 1)(2n + 1) 6 Find the sum of squares of the first 12 natural number​

Answer 1

Answer:

Given the sum of squares of first n natural numbers

=

6

1

n(n+1)×(2n+1)

The sum of squares of first 10 natural numbers

=

6

1

(10)(10+1)×(2×10+1)=

6

1

(10)(11)(21)=5×11×7=385