Math, asked by anitamewara61, 4 months ago

8. Madhu deposited 20000 in a bank at 10% per annum. Find the difference
compound interest after 1 years if the interest is compounded
(1) yearly (i) half-yearly​

Answers

Answered by bvchratnakumari1988
7

Answer:

Madhu diposited Rs 20000 in a bank,

Rate=10% per annum compounded half yearly,

Time=

2

3

years.

We know that,

Total amount= Principle+CI

For interest compounded half yearly,

Total amount =P(1+(

200

R

))

2n

=20000(1+(

200

10

))

2

3

=

200×200×200

20000×210×210×210

=22050

Interest=Amount−Principle

=22050−20000

=2050 Rs

Step-by-step explanation:

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Answered by harshitraj1562
12

Step-by-step explanation:

1.) Yearly:

P = 20000

r = 10%

t = 1year

amout= p(1 +  \frac{r}{100})^{n}

 = 20000(1 +  \frac{10}{100})^{1}

 = 20000( \frac{11}{10})

20000 \times  \frac{11}{10}  = 22000rs

C.I = Amount - Principle

= 22000 - 20000

= 2000 rs

2.) Compounded half yearly

amount = 20000(1 +  \frac{10}{200}){2}

 = 20000( \frac{21}{20})^{2}   \\  = 20000 \times  \frac{21}{20}  \times  \frac{21}{20}

 = 22050rs

C.I = 22050rs - 20000rs

=2050rs

Difference between half yearly C.I and yearly C.I

= 2050rs - 2000rs

= 50rs

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