Question

(8 marks)
d) A plane is flying at a height of 5,000 m above the sea level. At a point, it is exactly
b) Solve
20 5
Solve the following questions. Each question carries 2 marks.
a) Mark 5 and 6 on the number line and identify which is bigger.
b) Arrange the following rational numbers in ascending order: 13
1-40 (9-4)
c) Simplify:
-12 -4 9
and 1
6
8.
above a submarine floating 1.200 m below the sea level. What is the vertical
distance between the plane and the submarine?​

Answer 1

Answer:

Ka number of devices allowed by

Answer 2

$\underline{\green{\sf Question:}}$

✒Solve the following questions. Each question carries 2 marks.

➊Mark 5 and 6 on the number line and identify which is bigger.

➋Simplify: -12 -49 and 16

➌A plane is flying at a height of 5,000 m above the sea level. At a point, it is exactly above a submarine floating 1.200 m below the sea level. What is the vertical distance between the plane and the submarine?

$\underline{\green{\sf Solution:}}$

➔ A)

Given:

• 5 and 6

Find:

• Which is bigger

Solution:

we, have 5 and 6

Then, we say that 6 is bigger than 5. As we can simply see that 6 > 5

Hence, 5<6

_____________________

➔ B)

Given:

• - 12 - 49 and 16

Find:

• Simplify the given no.

Solution:

$\sf \hookrightarrow - 12 - 49 \: and \: 16$

$\sf \hookrightarrow - 12 - 49 + 16$

$\sf \hookrightarrow - 12 - 33$

$\sf \hookrightarrow - 45$

Hence, the answer will be -45

_______________________

➔ C)

Given:

• Distance of plane above the sea level = 5000m
• Distance of submarine below the sea level = -1.200m

[Distance below the sea level is taken as negative]

Find:

• Vertical Distance between the plane and the submarine

Solution:

we, know that

$\underline{\boxed{\sf Vertical \: distance = distance \: of \: plane + distance \: of \: submarine}}$

where,

• Distance of plane = 5000m
• Distance of submarine = -1.200m

So,

$\sf \to Vertical \: distance = distance \: of \: plane + distance \: of \: submarine$

$\sf \to Vertical \: distance =(5000) - ( - 1.200)$

$\sf \to Vertical \: distance =5000 + 1.200$

$\sf \to Vertical \: distance =5001.2m$

Hence, the vertical distance between the plane and the submarine will be 5001.2m