8. Maths teacher draws a figure on the board. In figure AB and CD are
straight lines.
Answers
Answer:
the figure is rectangle
Answer:
Step-by-step explanation:
Given : teacher draws a straight line AB
Raju to draw another line CD intersecting AB
∠AOD = 2c
∠AOC = 4b
Draw n ∠COE = 60° between C and B
∠BOE = b , ∠BOD = a
To Find : value of a , b & c
Solution:
∠AOC + ∠COE + ∠BOE = 180° ( linear pair) Straight line AB
4b + 60° + b = 180°
=> 5b = 120°
=> b = 24°
∠COE + ∠BOE + ∠DOB = 180° ( linear pair) Straight line CD
60° + b + a = 180°
=> 60° + 24° + a= 180°
=>a = 96°
or we could use a = 4b ( vertically opposite angle)
Hence a = 4(24) = 96°
a + 2c = 180° ( linear pair )
96° + 2c = 180°
=> 2c =84°
=> c = 42°
a = 96
b = 24
c = 42
a + 2c = 96 + 2(42) = 180°
2(24) + 42 = 90
2b + c = 90°
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