Math, asked by tanveerali439, 7 months ago

8 men 12 boys can complete work in 5 days and 6 men and 8 boys can complete work in 7 days find time taken by 1 man alone or that taken by 1 boy alone

Answers

Answered by adityanadimpalli8
0

Answer:

A car driver is traveling at a speed of 10m/s .

e.g., initial velocity , u = 10m/s

He applied break and brings to the car to rest in 20s.

so, time taken to stop the car = 20s

we have to find retardation.

final velocity of car , v = 0

use formula, v = u + at

0 = 10 + a20

a = -1/2 m/s² [hereative sign shows retardation ]

Step-by-step explanation:

Answered by MrCookie
0

Answer:

280 days

Step-by-step explanation:

Let the time taken by man be x days

time taken by boys be y days

work done by 1 man in one day=1/x

work done by 1 boy in one day=1/y

8/x+12/y = 1/10............eq 1

6/x+ 8/y = 1/14..........eq2

Let u=1/x & v=1/y

8u+ 12y=1/10.........eq3

6u+8v= 1/14...........eq4

Multiplying eq3 by 2 & eq4 by 3

16u+ 24y=2/10.........eq5

18u+24v= 3/14.........eq6

subtract eq 5 & 6

-2u= -3/14+2/10

-2u = (-3×10 +2×14)/140

-2u=( -30+28)/140

-2u=-2/140

u=1/140

put this value in eq 5

16u+ 24y=2/10

16×1/140 +24y =1/5

4/35+24y= 1/5

24y= 1/5-4/35

24y= (1×7 -4)/35

24y = (7-4)/35

24y= 3/35

y= 3/35×24

y= 1/280

u=1/x

1/140 = 1/x

x=140

v=1/y

1/280 = 1/y

y=280

A man complete the work in 140 days

A boy can complete the work in 280 days

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