Question

8 men and 12 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be?​

Answer 1

Step-by-step explanation:

Explanation : Let 1 man's 1 day's work = x and 1 boy's 1 day's work =y

Then 6x+8y =

10

1

and 26x+48y =

2

1

6x+8y =

10

1

........(1) ×6

26x+48y =

2

1

.........(2)

Solving these two equations we get :x=

100

1

and y=

200

1

(15men+20boy)

′

s 1 day's work =

100

15

+

200

20

=

4

1

15 men and 20 boys can do the work in $$4$6x+8y =

10

1

days.